WebStep 1: Use slope form of tangent equation of parabola Equation of tangent to parabola y 2=4ax in terms of slope ’m’ is y=mx+ ma Hence, tangent to given parabola y 2=16x is y=mx+ m4 [Since, a = 4] Substituting in equation of curve xy=−4 we get mx 2+ m4 x+4=0 ... (1) This is a quadratic equation in terms of x WebAug 11, 2024 · The equation of the tangent to the parabola y2 = 4ax is m2x − my + a = 0 this equation also satisfies x2 = 4by because you want a common tangent thus it …
Solved Use this to find the equation of the tangent line to - Chegg
Web`sqrt(3)y = x + 3` Explanation: Since, the equation of tangent to parabola `y^2 = 4x` is `y = mx + 1/m` .....(i) The line (1) is also the tangent to circle `x^2 + y^2 - 6x` = 0. Then centre of circle = (3, 0) Radius of circle = 3. The radius of the circle is equal to the perpendicular distance from the centre to the tangent. WebNov 25, 2024 · The equations of the common tangents to the parabola y = x2 and y = − (x − 2)2 y = x 2 and y = - ( x - 2) 2 is/are : A. y=0, y=4 (x-1) B. y=0, y=-4 (x-1) C. y=0, y=-30x-50 D. none of these class-11 parabola Share It On 1 Answer 0 votes answered Nov 25, 2024 by DevikaKumari (70.3k points) selected Nov 25, 2024 by TanujKumar Best answer temp spain number
Two parabolas with a common vertex and with axes along x-axis and y ...
WebCorrect option is A) let the common tangent be y=mx+c→(i) y 2=4ax→(ii) from (i) and (ii), point of intersect. m 2x 2+x(2mc−4a)x+c 2=0D=0b 2−4ac=0→(4)from(3)and(4)16a … WebIf we start at the vertex (it does not matter where it is on the graph), go over 1 and count how much you go up or down to determine the magnitude. Several examples and for … WebOct 30, 2024 · Using the point slope formula, the tangent line equation is y = m x - m 2 Thus the b value is - m 2 For the circle the procedure is the same but more complicated. I start by looking for a point of tangency in the fourth quadrant. temp spain